Hi,

__FUNCTION__ can give the function name. Is there any variable for
class name?

Thanks,
Peng

"Peng Yu" <PengYu.UT@gmail.comwrote in message
news:a8eebfae-9739-4967-8fbf-06f9d2da31fa@k37g2000hsf.googlegroups.com...If you are lucky, typeid( *this ).name()
Lucky meaning it may do so on some implementations, others it may not.
..name() is not guaranteed to have any value afaik.

On my system, and compiler (VC++ Express 2008) the following program
outputs:
class Foo

Your mileage may vary.

#include <iostream>

class Foo
{
public:
Foo()
{
std::cout << typeid( *this ).name() << "\n";
}
};

int main()
{
Foo Bar;
}

On Jul 10, 3:25 pm, "Jim Langston" <tazmas...@rocketmail.comwrote:Similarly, if you're lucky enough to get to use GCC,
__PRETTY_FUNCTION__ should contain the scoping namespaces/classnames
(and return and argument types). So, some parsing required....

Tony