Nick Keighley wrote:
Quote:
Quote: Quote:
>>how do I convert back a boost shared_ptr into a reference?
>>The function is as follows:
>>const myclass& myfunc() const
>>{
>> //I have a boost shared_ptr here;
>> // but I have to return "const myclass &"
>>}
>>How to do that?
| >return * my_pointer;
>>
>?
>>
>* is pronounced "dereference"...
| >
will code like this cause a problem
>
const myclass& myfunc() const
{
boost::shared_ptr<myclassmy_pointer (new myclass());
return *my_pointer;
}
>
will the newsed object be destroyed as the shared_ptr
goes out of scope? If not when does it get destroyed?
|
CC'd to the correct newsgroup.
Yes, the destructor of the shared pointer will delete the object. Then its
former address will convert to a reference. At some point - possibly the
conversion - Undefined Behavior will begin. And then when whoever collects the
reference uses it, Undefined Behavior will continue.
Why are you trying to do this? myfunc should just return a shared_ptr...
--
Phlip
Re: how do I convert back a boost shared_ptr into a reference? 
